(3x-4)(x^2-3x+1)=

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Solution for (3x-4)(x^2-3x+1)= equation: 


Simplifying
(3x + -4)(x2 + -3x + 1) = 0

Reorder the terms:
(-4 + 3x)(x2 + -3x + 1) = 0

Reorder the terms:
(-4 + 3x)(1 + -3x + x2) = 0

Multiply (-4 + 3x) * (1 + -3x + x2)
(-4(1 + -3x + x2) + 3x * (1 + -3x + x2)) = 0
((1 * -4 + -3x * -4 + x2 * -4) + 3x * (1 + -3x + x2)) = 0
((-4 + 12x + -4x2) + 3x * (1 + -3x + x2)) = 0
(-4 + 12x + -4x2 + (1 * 3x + -3x * 3x + x2 * 3x)) = 0
(-4 + 12x + -4x2 + (3x + -9x2 + 3x3)) = 0

Reorder the terms:
(-4 + 12x + 3x + -4x2 + -9x2 + 3x3) = 0

Combine like terms: 12x + 3x = 15x
(-4 + 15x + -4x2 + -9x2 + 3x3) = 0

Combine like terms: -4x2 + -9x2 = -13x2
(-4 + 15x + -13x2 + 3x3) = 0

Solving
-4 + 15x + -13x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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